при каких n число 2^2^2^2....^2 + 9 (n двоек) – простое?

+ 0 -

Adeniki

13 апр. 2014 г., 5:26:36 (10 лет назад)

F(a, b, с, d, e, f, g, h, i, j, k, l, m, n, o, p, q, r, s, t, u, v, w, x, y, z) =
    = {k + 2} {1 – (wz + h + j – q)2 – (2n + p + q + z – e)2
    – (a2y2 – y2 + 1 – x2)2 – ({e4 + 2e3}{a + 1}2 + 1 – o2)2
    – (16{k + 1}3{k + 2}{n + 1}2 + 1 – f 2)2
    – ({(a + u4 – u2a)2 – 1}{n + 4dy}2 + 1 – {x + cu}2)2
    – (ai + k + 1 – l – i)2
    – ({gk + 2g + k + 1}{h + j} + h – z)2
    – (16r2y4{a2 – 1} + 1 – u2)2
    – (p – m + l{a – n – 1} + b{2an + 2a – n2 – 2n – 2})2
    – (z – pm + pla – p2l + t{2ap – p2 – 1})2
    – (q – x + y{a – p – 1} + s{2ap + 2a – p2 – 2p – 2})2
    – (a2l2 – l2 + 1 – m2)2 – (n + l + v – y)2}.