Пожалуйста помогите как сможете срочнооо

1) log3.2 (2-x) = log3.2 (3x+6)
2) log0.8 (1+2x) = log0.8 (4x-10)
3) log2 (x-6)+ log2 (x-8) = 3
4) log8 (x-2) - log8 (x-3) = 1/3

1) lg (5-x) = 1/3lg (35-x^3)
2) log2 x-5/x+5 + log2 (x+5) = 0
3) log2 (3x-6) - 1 = log2 (9x-19)

1)log7 (x-2) + log7 (x+2) = log7 (4x+41)
2) log4 (x+1) - log4 (1-x) = log4 (2x+3)
3) log4 (x+3) - log4 (x-1) = 2 - log4 8
4) lg (x-1) + lg (x+1) = 3lg2 + lg (x-2)

1) 2 log3 (x-2) + log3 (x-4)^2 = 0
2) 2lgx - lg4 + lg (5-x^2) = 0
3) lg [x(x+9)] + lg x+9/x = 0

Nastn19042000 26 авг. 2013 г., 23:49:45 (10 лет назад)

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